10.publicclassBar{ 11.staticvoidfoo(int...x){ 12.//insertcodehere 13.} 14.} Which two code fragments,inserted independently at line1 2,will allow the class to compile()
public class Threads 1 { intx=0; public class Runner implements Runnable { public void run() { int current = 0; for(int=i=0;i<4;i++){ current = x; System.out.print(current + “, “); x = current + 2; } } } public static void main(String[] args) { new Threads1().go(); } public void go() { Runnable r1 = new Runner(); new Thread(r1).start(); new Thread(r1 ).start(); } } Which two are possible results?()
若有定义:intx;以下不会产生死循环的是()
一个函数为voidf(intx,chary=‘a’),另一个函数为voidf(int),则它们()。
main() {intx=3,i; for(i=0;i<3;i++)printf(""%d"",f(x)); } intf(inta) {intb=0; staticc=3; b++;c++; return(a+b+c); } 执行此程序后屏幕上显示的结果是什么:()
设有说明语句:intx,a,b,c;doubled=3.14;,以下不符合C语言语法的表达式是()
有如下类声明“classA{intx;……};”,则A类的成员x是()
设有程序段:intx=0,s=0;while(x!=0)s+=++x;printf("%d",s);,则运行程序段后()
设有说明:charw;intx;floaty;doublez;则表达式w*x+z-y值的数据类型为()。
关于下面的程序,说法正确的是()。intx=-1;do{x=x*x;}while(!x);