单选题
发布日期:2020-04-10
SELECT last_name, department_name FROM employees , departments(+);
SELECT last_name, department_name FROM employees JOIN departments(+);
SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments d
SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);
SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
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